In this section, we introduce a new mathematical tool called a logarithm, which will help us solve exponential equations.
Suppose that a colony of bacteria doubles in size every day. If the colony starts with \(50\) bacteria, how long will it be before there are \(800\) bacteria? We answered questions of this type in Section 4.2 by writing and solving an exponential equation. The function
The solution of this equation is the answer to the following question:
To what power must we raise \(2\) in order to get \(16\text{?}\)
The value of \(t\) that solves the equation is called the base \(2\) logarithm of \(16\text{.}\) Because \(2^4 = 16\text{,}\) the base \(2\) logarithm of \(16\) is \(4\text{.}\) We write this as
\begin{equation*}
\log_{2}16 = 4
\end{equation*}
In other words, we solve an exponential equation by computing a logarithm. You can check that \(t = \alert{4}\) solves the problem stated above:
Thus, the unknown exponent is called a logarithm. In general, for positive values of \(b\) and \(x\text{,}\) we make the following definition.
Definition of Logarithm.
For \(b\gt 0, b\ne 1\text{,}\) the base \(b\) logarithm of \(x\), written \(\log_{b} x\text{,}\) is the exponent to which \(b\) must be raised in order to yield \(x\text{.}\)
Note4.47.
It will help to keep in mind that a logarithm is just an exponent.
Some logarithms, like some square roots, are easy to evaluate, while others require a calculator. We will start with the easy ones.
To evaluate \(\log_3 9\text{,}\) we ask what exponent on base \(3\) will produce \(9\text{.}\) Or, 3 to what power equals 9? The exponent we need is \(\alert{2}\text{,}\) so
From the definition of a logarithm and the examples above, we see that the following two statements are equivalent.
Logarithms and Exponents: Conversion Equations.
If \(b \gt 0\text{,}\)\(b\ne 1\text{,}\) and \(x \gt 0\text{,}\)
\begin{equation*}
\blert{y = \log_b x}~~~ \text{ if and only if }~~~ \blert{ x = b^y}
\end{equation*}
In other words, the logarithm, \(y\text{,}\) is the same as the exponent in \(x = b^y\text{.}\) We see again that a logarithm is an exponent; it is the exponent to which \(b\) must be raised to yield \(x\text{.}\)
These equations allow us to convert from logarithmic to exponential form, or vice versa. You should memorize the conversion equations, because we will use them frequently.
As special cases of the equivalence in (1), we can compute the following useful logarithms. For any base \(b \gt 0, b\ne 1\text{,}\)
Some Useful Logarithms.
\begin{equation*}
\begin{aligned}[t]
\log_b b \amp = 1~~~ \text{ because } ~~~b^1 = b \\
\log_b 1 \amp = 0 ~~~ \text{ because } ~~~b^0 = 1 \\
\log_b{b^x} \amp = x~~~ \text{ because } ~~~b^x = b^x
\end{aligned}
\end{equation*}
We solve the first equation by taking a square root, and we solve the second equation by computing a logarithm:
\begin{equation*}
x = \pm\sqrt{25} = \pm 5 ~~~~ \text{ and } ~~~~ x = \log_{2}{8} = 3
\end{equation*}
The operation of taking a base \(b\) logarithm is the inverse operation for raising the base \(b\) to a power, just as extracting square roots is the inverse of squaring a number.
Every exponential equation can be rewritten in logarithmic form by using the conversion equations. Thus,
First identify the base \(b\text{,}\) and then the exponent or logarithm \(y\text{.}\) Use the conversion equations to rewrite \(b^y = x\) in the form \(\log_{b}{x} = y\text{.}\)
The base is \(2\) and the exponent is \(-1\text{.}\) Thus, \(\log_{2}{\dfrac{1}{2}}= -1\text{.}\)
The base is \(a\) and the exponent is \(\dfrac{1}{5}\text{.}\) Thus, \(\log_{a}{2.8} = \dfrac{1}{5}\text{.}\)
The base is \(6\) and the exponent is \(1.5\text{.}\) Thus, \(\log_{6}{T} = 1.5\text{.}\)
The base is \(M\) and the exponent is \(v\text{.}\) Thus, \(\log_{M}{3K} = v\text{.}\)
Checkpoint4.56.Practice 3.
Rewrite each equation in logarithmic form.
\(8^{-1/3} = \dfrac{1}{2}\)
The given equation is equivalent to one of the form \(\log_{b}m=n\text{,}\) where
\(b=\)
\(m=\), and
\(n=\)
\(5^x = 46\)
The given equation is equivalent to one of the form \(\log_{b}m=n\text{,}\) where
If \(\log_2 x\) is negative, what can you say about \(x\text{?}\)
SubsectionApproximating Logarithms
Suppose we would like to solve the equation
\begin{equation*}
2^x = 26
\end{equation*}
The solution of this equation is \(x = \log_{2}{26}\text{,}\) but can we find a decimal approximation for this value? There is no integer power of \(2\) that equals \(26\text{,}\) because
Thus, \(\log_{2}{26}\) must be between \(4\) and \(5\text{.}\) We can use trial and error to find the value of \(\log_{2}{26}\) to the nearest tenth. Use your calculator to make a table of values for \(y = 2^x\text{,}\) starting with \(x = 4\) and using increments of \(0.1\text{.}\)
\(x\)
\(2^x\)
\(x\)
\(2^x\)
\(4\)
\(2^4=16\)
\(4.5\)
\(2^{4.5}=22.627\)
\(4.1\)
\(2^{4.1}=17.148\)
\(4.6\)
\(2^{4.6}=24.251\)
\(4.2\)
\(2^{4.2}=18.379\)
\(\alert{4.7}\)
\(2^{\alert{4.7}}=25.992\)
\(4.3\)
\(2^{4.3}=19.698\)
\(\alert{4.8}\)
\(2^{\alert{4.8}}=27.858\)
\(4.4\)
\(2^{4.4}=21.112\)
\(4.9\)
\(2^{4.9}=29.857\)
From the table we see that \(26\) is between \(2^{4.7}\) and \(2^{4.8}\text{,}\) and is closer to \(2^{4.7}\text{.}\) To the nearest tenth, \(\log_{2}{26} \approx 4.7\text{.}\)
Trial and error can be a time-consuming process. In Example 4, we illustrate a graphical method for estimating the value of a logarithm.
Example4.58.
Approximate \(\log_{3}{7}\) to the nearest hundredth.
If \(\log_{3}{7}=x\text{,}\) then \(3^x = 7\text{.}\) We will use the graph of \(y = 3^x\) to approximate a solution to \(3^x = 7\text{.}\)
We graph \(Y_1 =3\)^ X and \(Y_2 = 7\) in the standard window (ZOOM 6) to obtain the graph shown below. Next we activate the intersect feature to find that the two graphs intersect at the point \((1.7712437, 7)\text{.}\) Because this point lies on the graph of \(y = 3^x\) , we know that
\begin{equation*}
3^{1.7712437} \approx 7~~~\text{, or }~~~ \log_{3}{7} \approx 1.7712437
\end{equation*}
To the nearest hundredth, \(\log_{3}{7} \approx 1.77\text{.}\)
Checkpoint4.59.Practice 4.
Rewrite the equation \(3^x = 90\) in logarithmic form.
The given equation is equivalent to one of the form \(\log_{b}m=n\text{,}\) where
\(b=\)
\(m=\), and
\(n=\)
Use a graph to approximate the solution to the equation in part (a). Round your answer to three decimal places.
Some logarithms are used so frequently in applications that their values are programmed into scientific and graphing calculators. These are the base \(10\) logarithms, such as
Base \(10\) logarithms are called common logarithms, and the subscript \(10\) is often omitted, so that \(\log x\) is understood to mean \(\log_{10}{x}\text{.}\)
Checkpoint4.60.QuickCheck 4.
If \(\log x = 2.5\text{,}\) what can you say about \(x\text{?}\)
To evaluate a base \(10\) logarithm, we use the LOG key on a calculator. Many logarithms are irrational numbers, and the calculator gives as many digits as its display allows. We can then round off to the desired accuracy.
Example4.61.
Approximate the following logarithms to \(2\) decimal places.
The keying sequence LOG\(6.5\))ENTER produces the display
\(\log {(6.5)}\)
\(\)
\(\)
\(\)
\(\)
\(.812913566\)
so \(\log {6.5}\approx 0.81\text{.}\)
The keying sequence LOG\(256\))ENTER yields \(2.408239965\text{,}\) so \(\log {256} \approx 2.41\text{.}\)
Note4.62.
We can check the approximations found in Example 4.61 with our conversion equations. Remember that a logarithm is an exponent, and in this example the base is \(10\text{.}\) We find that
Explain how to estimate \(\log_{10} x\) between two integers.
SubsectionSolving Exponential Equations
We can now solve any exponential equation with base \(10\text{.}\) For instance, to solve the equation \(16 \cdot 10^t = 360\text{,}\) we first divide both sides by \(16\) to obtain
\begin{equation*}
10^t = 22.5
\end{equation*}
Then we convert the equation to logarithmic form and evaluate:
\begin{equation*}
t = \log_{10}{22.5} \approx 1.352182518
\end{equation*}
To \(4\) decimal places, the solution is \(1.3522\text{.}\)
To solve exponential equations involving powers of 10, we can use the following steps.
Steps for Solving Base 10 Exponential Equations.
Isolate the power on one side of the equation.
Rewrite the equation in logarithmic form.
Use a calculator, if necessary, to evaluate the logarithm.
Solve for the variable.
Example4.65.
Solve the equation \(~~38 = 95 - 15 \cdot 10^{0.4x}\)
\begin{equation*}
\frac{\log_{10}{3.8}}{0.4}= x
\end{equation*}
We can evaluate this expression on the calculator by entering
LOG\(3.8\))÷\(0.4\)ENTER
which yields \(1.449458992\text{.}\) Thus, to four decimal places, \(x \approx 1.4495\text{.}\)
Caution4.66.
Be careful when using a calculator to evaluate expressions involving logs. We can evaluate a single logarithm like \(\log{3.8}\) by entering LOG\(3.8\)ENTER without an ending parenthesis, so that the calculator shows
\(\log {(3.8}\)
\(\)
\(\)
\(\)
\(\)
\(.5795835966\)
But if we want to evaluate \(\dfrac{\log{3.8}}{0.4}\text{,}\) we must enclose \(3.8\) in parentheses, as shown in Example 4.65. If we omit the parenthesis after \(3.8\text{,}\) the calculator will interpret the expression as \(\log{\left(\dfrac{3.8}{0.4}\right)}\text{,}\) which is not the expression we wanted.
Checkpoint4.67.QuickCheck 5.
What is the first step in solving the equation \(5(10)^x=12\text{?}\)
We have seen that exponential functions are used to describe some applications of growth and decay, \(P(t) = P_0b^t\text{.}\) There are two common questions that arise in connection with exponential models:
Given a value of \(t\text{,}\) what is the corresponding value of \(P(t)\text{?}\)
Given a value of \(P(t)\text{,}\) what is find the corresponding value of \(t\text{?}\)
To answer the first question, we evaluate the function \(P(t)\) at the appropriate value. To answer the second question, we must solve an exponential equation, and this usually involves logarithms.
Example4.69.
The value of a large tractor originally worth $\(30,000\) depreciates exponentially according to the formula
No, the percent of homes with computers cannot exceed \(100\%\text{.}\)
At this stage, it seems we will only be able to solve exponential equations in which the base is \(10\text{.}\) However, we will see in Section 4.4 how the properties of logarithms enable us to solve exponential equations with any base.
Checkpoint4.71.Pause and Reflect.
The population of rabbits on an island grows according to \(P(t)=6(10)^{0.3t}\text{.}\) Explain the difference between the two problems: (1) given \(P\) find \(t\text{,}\) and (2) given \(t\) find \(P\text{.}\)
SubsectionSection Summary
SubsubsectionVocabulary
Look up the definitions of new terms in the Glossary.
Logarithm
Common logarithm
SubsubsectionCONCEPTS
We use logarithms to help us solve exponential equations.
The base \(b\) logarithm of \(x\), written \(\log_b x\text{,}\) is the exponent to which \(b\) must be raised in order to yield \(x\text{.}\)
If \(b\gt 0\) and \(x \gt 0\text{,}\)
\begin{equation*}
y=\log_b x ~~~ \text{ if and only if } ~~~x=b^y
\end{equation*}
The operation of taking a base \(b\) logarithm is the inverse operation for raising the base \(b\) to a power.
Base \(10\) logarithms are called common logarithms, and \(\log x\) means \(\log_{10} x\text{.}\)
Steps for Solving Base 10 Exponential Equations.
Isolate the power on one side of the equation.
Rewrite the equation in logarithmic form.
Use a calculator, if necessary, to evaluate the logarithm.
Solve for the variable.
SubsubsectionSTUDY QUESTIONS
To find \(\log_6 27\) means to find an exponent \(\) that satisfies the equation .
Can a logarithm be a negative number?
Evaluate the following logarithms:
\(\displaystyle \log_8 8^{15}\)
\(\displaystyle \log_5 5^{\sqrt{13}}\)
\(\displaystyle \log_b b^{2.63}\)
Guess the solution of \(10^x = 750\text{.}\) Now find an approximation correct to four decimal places. Was your guess too big or too small?
SubsubsectionSKILLS
Practice each skill in the Homework problems listed.
Compute logs base \(b\) using the definition: #1–10, 59–66
Convert from exponential to logarithmic form: #11–22
Approximate logarithms: #23–34
Solve exponential equations base 10: #35–48
Solve application problems: #49–58
ExercisesHomework 4.3
Exercise Group.
For Problems 1–10, find each logarithm without using a calculator.
1.
\(\displaystyle \log_7 49\)
\(\displaystyle \log_2 32 \)
2.
\(\displaystyle \log_4 64\)
\(\displaystyle \log_3 27 \)
3.
\(\displaystyle \log_3 \sqrt{3} \)
\(\displaystyle \log_3 \dfrac{1}{3} \)
4.
\(\displaystyle \log_5 \dfrac{1}{5} \)
\(\displaystyle \log_5 \sqrt{5} \)
5.
\(\displaystyle \log_4 4 \)
\(\displaystyle \log_6 1 \)
6.
\(\displaystyle \log_{10} 1 \)
\(\displaystyle \log_{10} 10^{-6} \)
7.
\(\displaystyle \log_8 8^5 \)
\(\displaystyle \log_7 7^6 \)
8.
\(\displaystyle \log_{10} 10^{-4} \)
\(\displaystyle \log_{10} 10^{-6} \)
9.
\(\displaystyle \log_{10} 0.1 \)
\(\displaystyle \log_{10} 0.001 \)
10.
\(\displaystyle \log_{10} 10,000 \)
\(\displaystyle \log_{10} 1000 \)
Exercise Group.
For Problems 11–22, rewrite the equation in logarithmic form.
11.
\(2^{10}=1024 \)
12.
\(11^{4}=14,641 \)
13.
\(10^{0.699}\approx 5 \)
14.
\(10^{-0.602}\approx 0.25 \)
15.
\(t^{3/2}=16 \)
16.
\(v^{5/3}=12 \)
17.
\(0.8^{1.2}=M \)
18.
\(3.7^{2.5}=Q \)
19.
\(x^{5t}=W-3 \)
20.
\(z^{-3t}=2P+5 \)
21.
\(3^{-0.2t}=2N_0 \)
22.
\(10^{1.3t}=3M_0 \)
Exercise Group.
For Problems 23–26,
Solve each equation, writing your answer as a logarithm.
Use trial and error to approximate the logarithm to one decimal place.
23.
\(4^x=2.5 \)
24.
\(2^x=0.2 \)
25.
\(10^x=0.003 \)
26.
\(10^x=4500 \)
Exercise Group.
For Problems 27–30,
By computing successive powers of the base, trap each log between two integers.
Use a graph to approximate each logarithm to the nearest hundredth. (Hint: Use the conversion equations to rewrite \(x = \log_b y\) as an appropriate exponential equation.)
27.
\(\log_{10} 7 \)
28.
\(\log_{10} 50 \)
29.
\(\log_{3} 67.9 \)
30.
\(\log_{5} 86.3 \)
Exercise Group.
For Problems 31–34, use a calculator to approximate each logarithm to four decimal places. Make a conjecture about logarithms based on the results of each problem.
31.
\(\displaystyle \log_{10} 5.43\)
\(\displaystyle \log_{10} 54.3\)
\(\displaystyle \log_{10} 543\)
\(\displaystyle \log_{10} 5430\)
32.
\(\displaystyle \log_{10} 0.625\)
\(\displaystyle \log_{10} 0.0625\)
\(\displaystyle \log_{10} 0.00625\)
\(\displaystyle \log_{10} 0.000625\)
33.
\(\displaystyle \log 2\)
\(\displaystyle \log 4 \)
\(\displaystyle \log 8 \)
\(\displaystyle \log 16\)
34.
\(\displaystyle \log 4\)
\(\displaystyle \log 0.25\)
\(\displaystyle \log 5\)
\(\displaystyle \log 0.2\)
Exercise Group.
For Problems 35–44, solve for \(x\text{.}\) Round your answers to hundredths.
35.
\(10^{-3x}=5 \)
36.
\(10^{-5x}=76 \)
37.
\(25\cdot 10^{0.2x}=80 \)
36.
\(8\cdot 10^{1.6x}=312 \)
39.
\(12.2=2\left(10^{1.4x}\right)-11.6 \)
40.
\(163=3\left(10^{0.7x}\right)-49.3 \)
41.
\(3\left(10^{-1.5x}\right)-14.7=17.1 \)
42.
\(4\left(10^{-0.6x}\right)+16.1=28.2 \)
43.
\(80\left(1-10^{-0.2x}\right) =65 \)
44.
\(250\left(1-10^{-0.3x}\right) =100 \)
Exercise Group.
In Problems 45–48, each calculation contains an error. Find and correct it.
where \(t\) is measured in years since \(1990\text{.}\)
What was the population in \(2000\text{?}\)
Assuming the same rate of growth, estimate the population of New York in the years \(2010\text{,}\)\(2015\text{,}\) and \(2020\text{.}\)
When did the population of New York reach \(20,000,000\text{?}\)
When should the population reach \(30,000,000\text{?}\)
Graph the function \(P\) with a suitable domain and range, then verify your answers to parts (a) through (d).
51.
The absolute magnitude, \(M\text{,}\) of a star is a measurement of its brightness. For example, our Sun, not a particularly bright star, has magnitude \(M = 4.83\text{.}\) The magnitude in turn is a measure of the luminosity, \(L\text{,}\) or amount of light energy emitted by the star, where
\begin{equation*}
L = L_0 10^{-0.4M}
\end{equation*}
The luminosity of a star is measured in solar units, so that our Sun has luminosity \(L = 1\text{.}\) Use the values of \(L\) and \(M\) for the Sun to calculate a value of \(L_0\) in the equation above.
Is luminosity an increasing or decreasing function of magnitude? Graph the function on the domain \([-3, 3]\text{.}\) What is its range on that domain?
The luminosity of Sirius is \(22.5\) times that of the Sun, or \(L = 22.5\text{.}\) Calculate the magnitude of Sirius.
If two stars differ in magnitude by \(5\text{,}\) what is the ratio of their luminosities?
A decrease in magnitude by \(1\) corresponds to an increase in luminosity by what factor? Give an exact value and an approximation to four decimal places.
Normal stars have magnitudes between \(-10\) and \(19\text{.}\) What range of luminosities do stars exhibit?
52.
The loudness of a sound is a consequence of its intensity, \(I\text{,}\) or the amount of energy it generates, in watts per square meter. The intensity is related to the decibel level, \(D\text{,}\) which is another measure of loudness, by
\begin{equation*}
I = 10^{-12+D/10}
\end{equation*}
Is intensity an increasing or decreasing function of decibel level? The faintest sound a healthy human can hear is \(0\) decibels. What is the intensity of a \(0\) decibel sound?
A whisper produces an energy intensity of \(10^{-9}\) watts per square meter. What is the decibel level of a whisper?
If two sounds differ in loudness by \(10\) decibels, what is the ratio of their intensities?
An increase in loudness of \(1\) decibel produces a just noticeable difference to the human ear. By what factor does the intensity increase?
Sounds of \(130\) decibels are at the threshold of pain for people. What is the range of the intensity function on the domain \([0, 130]\text{?}\)
Exercise Group.
The atmospheric pressure decreases with altitude above the surface of the Earth. For Problems 53–58, use the function